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You can put this solution on YOUR website!
Call the rate of speed of train B = B.
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document.write( "Call the rate of speed of train A = B-20
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document.write( "Do that because the problem said A's rate is 20 mph less than B's.
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document.write( "D=rt for both, and the t is the same.
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document.write( "Train A:
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document.write( "Divide both sides by B-20, so
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document.write( "Train A:
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document.write( "Train B:
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document.write( "Divide both sides by B.
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document.write( "Train B:
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document.write( "t is the same in both cases, so set the equations equal to each other.
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document.write( "Cross multiply.
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document.write( "Subtract 290B from both sides.
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document.write( "Divide both sides by -100.
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document.write( "Train B's rate = B = 58 mph.
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document.write( "Train A's rate = B-20 = 58-20 = 38mph
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