document.write( "Question 537502: A committee of four people are to be chosen from six Democrats and four Republicans. Find the probability that two are Democrats and two are Republicans. Express your answer as a fraction reduced to lowest terms \n" ); document.write( "
Algebra.Com's Answer #352887 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A committee of four people are to be chosen from six Democrats and four Republicans. Find the probability that two are Democrats and two are Republicans. Express your answer as a fraction reduced to lowest terms \n" ); document.write( "---- \n" ); document.write( "# of ways to succeed: 6C2*4C2 = 15*6 = 90 ways \n" ); document.write( "--- \n" ); document.write( "# of randomly chosen committee: 10C4 = 210 \n" ); document.write( "--- \n" ); document.write( "P(2Dems and 2Reps) = 90/210 = 9/21 = 3/7 \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "======================== \n" ); document.write( " |