document.write( "Question 537393: Train A and B are traveling in the same direction on paralel tracks. Train A is traveling 40mph and train B is traveling 48mph. Train A passes a station at 11:15 a.m. If train B passes the same station at 11:30a.m. at what time will train B catch up to train A \n" ); document.write( "
Algebra.Com's Answer #352870 by mananth(16949) You can put this solution on YOUR website! Train A 40 mph \n" ); document.write( "Train B 48 mph \n" ); document.write( "Train A 11:15 \n" ); document.write( "Train B 11:30 \n" ); document.write( "Difference in time= 00:15 => 0.25 hours \n" ); document.write( "Train A will have covered 10 miles before Train B starts \n" ); document.write( "catch up distance= 10 miles \n" ); document.write( "catch up speed = 48 -40 mph \n" ); document.write( "catch up speed = 8 mph \n" ); document.write( "Catchup time = catchup distance/catch up speed \n" ); document.write( "catch up time= 10 / 8 \n" ); document.write( "catch up time= 1.25 hours \n" ); document.write( "They will meet at 12:45 pm \n" ); document.write( "Train B speed = 48 mph \n" ); document.write( "Time to catch up = 1.25 hours 75minutes \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |