document.write( "Question 52939This question is from textbook Beginning Algebra
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\n" ); document.write( "\n" ); document.write( "One number is 7 less than another. If 4 times the smaller number plus 2 times the larger number is 62. find the two numbers... I have the answer but I don't how to get the answer..... \n" ); document.write( "

Algebra.Com's Answer #35285 by rchill(405) $\"\"$ $\"About$

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Let x represent one number; then x-7 is the number that is 7 less. Because x-7 is less than x, it's the smaller number. We have 4 times the smaller number (i.e., x-7) represented as 4(x-7); two time the larger number (i.e., x) is represented as 2x. So now our equation is $\"4%28x-7%29%2B2x=62\"$ . Expanding the equation we get $\"4x-28%2B2x=62\"$ which simplifies to $\"6x-28=62\"$ . Now just solve for x by adding 28 to both sides $\"6x=90\"$ and then dividing both sides by 6 to get $\"x=15\"$ . That means 15 is the larger of the two numbers, and the smaller number, represented by x-7, or 15-7, is 8. Therefore, the two numbers are 15 and 8. To check this, 4 times the smaller number (4*8=32) added to 2 times the larger (2*15=30) is 62 (32+30), and 8 is 7 less than 15. Therefore, 15 and 8 are correct!
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