document.write( "Question 537385: i need help on finding three consecutive odd intergers whose sum is 117 \n" ); document.write( "
Algebra.Com's Answer #352848 by algebrahouse.com(1659)\"\" \"About 
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three consecutive odd intergers whose sum is 117\r
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\n" ); document.write( "\n" ); document.write( "x = first odd integer
\n" ); document.write( "x + 2 = 2nd odd integer {odd integers increase by 2 each time}
\n" ); document.write( "x + 4 = 3rd odd integer\r
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\n" ); document.write( "\n" ); document.write( "x + x + 2 = x + 4 = 117 {their sum is 117}
\n" ); document.write( "3x + 6 = 117 {combined like terms}
\n" ); document.write( "3x = 111 {subtracted 6 from both sides}
\n" ); document.write( "x = 37 {divided both sides by 3}
\n" ); document.write( "x + 2 = 39 {substituted 37, in for x, into x + 2}
\n" ); document.write( "x + 4 = 41 {substituted 37, in for x, into x + 4}\r
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\n" ); document.write( "\n" ); document.write( "37, 39, and 41 are the three consecutive odd integers
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