document.write( "Question 537385: i need help on finding three consecutive odd intergers whose sum is 117 \n" ); document.write( "
Algebra.Com's Answer #352848 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! three consecutive odd intergers whose sum is 117\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = first odd integer \n" ); document.write( "x + 2 = 2nd odd integer {odd integers increase by 2 each time} \n" ); document.write( "x + 4 = 3rd odd integer\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + x + 2 = x + 4 = 117 {their sum is 117} \n" ); document.write( "3x + 6 = 117 {combined like terms} \n" ); document.write( "3x = 111 {subtracted 6 from both sides} \n" ); document.write( "x = 37 {divided both sides by 3} \n" ); document.write( "x + 2 = 39 {substituted 37, in for x, into x + 2} \n" ); document.write( "x + 4 = 41 {substituted 37, in for x, into x + 4}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "37, 39, and 41 are the three consecutive odd integers \n" ); document.write( " For more help from me, visit: www.algebrahouse.com \n" ); document.write( " |