document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=537331>Question 537331</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Freddie gets a car ride to the top of a hill, then rides his skateboard back down. The downhill ride takes 15 minutes longer than the uphill.  If the car averages 32 mph, and Freddie rides his skateboard at 8 mph, find out how much time he spends skateboarding.\r<BR>\n" );
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document.write( "Let t=time spent driving to the top of the hill then, t+15=time going down the hill.<BR>\n" );
document.write( "distance up=distance down<BR>\n" );
document.write( "from the formula speed=distance/time(s=d/t), then d=st, \r<BR>\n" );
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document.write( "32t=8(t+15)<BR>\n" );
document.write( "32t=8t+120\r<BR>\n" );
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document.write( "I can't get to the answer of 1/3 hour.  I keep coming up with 1/4 hour. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #352823 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=352823\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 15 minutes is 1/4 hr so t+1/4 not t+15\r<BR>\n" );
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document.write( "32t=8(t+1/4)<BR>\n" );
document.write( "32t=8t+2<BR>\n" );
document.write( "24t=2<BR>\n" );
document.write( "t=1/12 hour.<BR>\n" );
document.write( "t=5 minutes<BR>\n" );
document.write( "5+15=20 minutes<BR>\n" );
document.write( "20/60=1/3 hour  skateboarding\r<BR>\n" );
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document.write( "If you use t+15 then you get t=5 but 5 means 5 hours not 5 minutes!!! </SPAN>\n" );
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