document.write( "Question 537263: Beth, Bill, and Edie, can paint a house together in 10 hours. BIll and Edie together can paint the same house in 15 hours. One day, all three worked on the same kind of house for 4 hours, after which Edie left. Beth and BIll required 8 more hours to finish. Assuming no gain or loss in efficiency, how long should it take each person to complete such a job alone? \n" ); document.write( "
Algebra.Com's Answer #352778 by richwmiller(17219)\"\" \"About 
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Beth=h
\n" ); document.write( "Bill=b
\n" ); document.write( "Edie=d
\n" ); document.write( "10/h+10/b+10/d=1
\n" ); document.write( "15/b+15/d=1\r
\n" ); document.write( "\n" ); document.write( "4/h+4/b+4/d+8/h+8/b=1
\n" ); document.write( "b=24
\n" ); document.write( "d=40
\n" ); document.write( "h=30
\n" ); document.write( "check
\n" ); document.write( "10/30+10/24+10/40=1
\n" ); document.write( "40+50+30/120=1
\n" ); document.write( "120/120=1
\n" ); document.write( "ok
\n" ); document.write( "15/24+15/40=1
\n" ); document.write( "5/8+3/8=1
\n" ); document.write( "8/8=1
\n" ); document.write( "ok\r
\n" ); document.write( "\n" ); document.write( "4/30+4/24+4/40+8/30+8/24=1
\n" ); document.write( "(16+20+12)/120+4/15+4/12=1
\n" ); document.write( "4/10+4/15+1/3=1
\n" ); document.write( "2/5+4/15+5/15
\n" ); document.write( "(6+4+5)/15=1
\n" ); document.write( "15/15=1
\n" ); document.write( "ok\r
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