document.write( "Question 537174: The problem is... solve the equation on the interval 0 less than/equal to theta and 2pi is greater than theta... and the equation is 2sqrt(3) sin (4theta) = 3
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document.write( "interval 0≤θ<2π\r
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document.write( "2√ 3 sin (4θ) = 3\r
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document.write( "The answers that the book got were { pi/12, pi/6, 2pi/3, 7pi/6,13pi/12, 5pi/3, 19pi/12}... and I want to know how they got those answers please (step by step would be great) \r
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Algebra.Com's Answer #352763 by KMST(5328)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "Teachers like to give students a chart, or better yet a printed circle, with the angle measurements and exact values for sine, cosine, tangent for certain notable angles, so that number may ring a bell. You do not need to memorize them, or have the chart because they all derive from Pythagoras theorem and triangles that are half of a square or half or an equilateral triangle. However, having such a chart helps keep your calculations straight. \n" ); document.write( "You should know that \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Dividing by 4, we get the values for \n" ); document.write( " |