document.write( "Question 537203: You are to take a multiple-choice exam consisting of 100 questions with 5 possible responses to each question. Suppose that you have not studied and so must guess (select one of the five answers in a completely random fashion) on each question. Let x represent the number of correct responses on the test.
\n" ); document.write( "a) what kind of probability does x have?
\n" ); document.write( "b) What is your expected score on the exam?
\n" ); document.write( "c) Compare the variance and standard deviation of x.
\n" ); document.write( "d) based on your answers to parts b and c, is it likely that you would score over 50 on this exam? explain your reasoning behind your answer
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Algebra.Com's Answer #352760 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
You are to take a multiple-choice exam consisting of 100 questions with 5 possible responses to each question. Suppose that you have not studied and so must guess (select one of the five answers in a completely random fashion) on each question. Let x represent the number of correct responses on the test.
\n" ); document.write( "a) what kind of probability does x have?:::binomial with n = 100 and p = 1/5
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\n" ); document.write( "b) What is your expected score on the exam?
\n" ); document.write( "expected = np = 100*(1/5) = 20
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\n" ); document.write( "c) Compare the variance and standard deviation of x.
\n" ); document.write( "std = sqrt(100*1/5*4/5) = 4
\n" ); document.write( "var = std^2 = 16
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\n" ); document.write( "d) based on your answers to parts b and c, is it likely that you would score over 50 on this exam? explain your reasoning behind your answer
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\n" ); document.write( "z(50) = (50-20)/4 = 30/4 = 7 1/2 standard deviations
\n" ); document.write( "Since 50 is 7 1/2 standard deviations above the mean
\n" ); document.write( "it is highly unlikely a person would score over 50
\n" ); document.write( "with no study.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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