document.write( "Question 537122: i need help with the following problem:\r
\n" ); document.write( "\n" ); document.write( "solve for x: x/x+5 - 5/x-5= x^2+25/x^2-25\r
\n" ); document.write( "\n" ); document.write( "find LCM of: x^2+8x+16 and x^2+x-12\r
\n" ); document.write( "\n" ); document.write( "im just not sure about the process? im not even really sure how to start.
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Algebra.Com's Answer #352732 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( "\"x%2F%28x%2B5%29-5%2F%28x-5%29+=+%28x%5E2%2B25%29%2F%28x%5E2-25%29\" I would first add the two fractions on the left side using the LCD of \"%28x%2B5%29%28x-5%29\"
\n" ); document.write( " Simplify the left side.
\n" ); document.write( "\"%28x%5E2-5x-5x-25%29%2F%28x%2B5%29%28x-5%29+=+%28x%5E2%2B25%29%2F%28x%5E2-25%29\" Now factor the denominator on the right side.
\n" ); document.write( "\"%28x%5E2-10x-25%29%2F%28x%2B5%29%28x-5%29+=+%28x%5E2%2B25%29%2F%28x%2B5%29%28x-5%29\" Multiply both sides by \"%28x%2B5%29%28x-5%29\".
\n" ); document.write( "\"x%5E2-10x-25+=+x%5E2%2B25\" Subtract \"x%5E2\" from both sides.
\n" ); document.write( "\"-10x-25+=+25\" Add 25 to both sides.
\n" ); document.write( "\"-10x+=+50\" Finally, divide both sides by -10.
\n" ); document.write( "\"highlight%28x+=+-5%29\"
\n" ); document.write( "However, when you try to check this solution by substituting \"x+=+-5\" in the original equation, you will have division by zero in two of the terms, which means that this solution is invalid.
\n" ); document.write( "This equation, therefore, has no solution!
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