document.write( "Question 536960: Casey and David leave school at the same time and drive in opposite directions. Casey travels at a speed that is 15 mph faster than David. After 3 hours, they are 261 miles apart. Find the rateof speed for both Casey and David \n" ); document.write( "
Algebra.Com's Answer #352688 by mananth(16946)\"\" \"About 
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David x mph
\n" ); document.write( "Casey x+ 15 mph
\n" ); document.write( "..
\n" ); document.write( "They are moving away from each other
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\n" ); document.write( "So add up their speed.
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\n" ); document.write( "combined speed = x+ 1 x + 15
\n" ); document.write( "( 2 x + 15 )
\n" ); document.write( "Time = 3 hours
\n" ); document.write( "Distance = 261 miles
\n" ); document.write( "Distance = speed * time
\n" ); document.write( "( 2 x 15 )* 3 = 261
\n" ); document.write( "6 x + 45 = 261
\n" ); document.write( "6 x = 261 + -45
\n" ); document.write( "6 x = 216
\n" ); document.write( "/ 6
\n" ); document.write( "x= 36 mph David
\n" ); document.write( "Casey 36 + 15 = 51 mph
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