document.write( "Question 536960: Casey and David leave school at the same time and drive in opposite directions. Casey travels at a speed that is 15 mph faster than David. After 3 hours, they are 261 miles apart. Find the rateof speed for both Casey and David \n" ); document.write( "
Algebra.Com's Answer #352688 by mananth(16946)![]() ![]() You can put this solution on YOUR website! David x mph \n" ); document.write( "Casey x+ 15 mph \n" ); document.write( ".. \n" ); document.write( "They are moving away from each other \n" ); document.write( " \n" ); document.write( "So add up their speed. \n" ); document.write( " \n" ); document.write( "combined speed = x+ 1 x + 15 \n" ); document.write( "( 2 x + 15 ) \n" ); document.write( "Time = 3 hours \n" ); document.write( "Distance = 261 miles \n" ); document.write( "Distance = speed * time \n" ); document.write( "( 2 x 15 )* 3 = 261 \n" ); document.write( "6 x + 45 = 261 \n" ); document.write( "6 x = 261 + -45 \n" ); document.write( "6 x = 216 \n" ); document.write( "/ 6 \n" ); document.write( "x= 36 mph David \n" ); document.write( "Casey 36 + 15 = 51 mph \n" ); document.write( " \n" ); document.write( " |