document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=536996>Question 536996</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A motorboatleaves a harbor and travels at an average speed of 9mph toward a small island. Two hours later, a cabin cruiser leaves the same harbor and travels at an average speed of 18mph toward the same island. In how many hours after the cabin cruiser leaves will the cabin cruiser be alongside with the motorboat.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #352686 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=352686\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Motorboat speed 	9	mph					<BR>\n" );
document.write( "cabin cruiser	18	mph					<BR>\n" );
document.write( "Difference in time=>	2	hours		<BR>\n" );
document.write( "Motorboat  	will have covered miles	before 	cabin cruiser starts<BR>\n" );
document.write( "catch up distance=		18	miles				<BR>\n" );
document.write( "catch up speed =		18	-9	mph			<BR>\n" );
document.write( "catch up speed =		9	mph				<BR>\n" );
document.write( "Catchup time = catchup distance/catch up speed							<BR>\n" );
document.write( "catch up time=		18	/	9			<BR>\n" );
document.write( "catch up time=		2	hours	\r<BR>\n" );
document.write( "\n" );
document.write( "m.ananth@hotmail.ca			<BR>\n" );
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