document.write( "Question 537000: Solve using the square root property
\n" ); document.write( "(x+6)^2=14
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Algebra.Com's Answer #352681 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"%28x%2B6%29%5E2=14\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B6=%22%22%2B-sqrt%2814%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B6=sqrt%2814%29\" or \"x%2B6=-sqrt%2814%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "\"x=-6%2Bsqrt%2814%29\" or \"x=-6-sqrt%2814%29\" Subtract \"6\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=-6%2Bsqrt%2814%29\" or \"x=-6-sqrt%2814%29\".\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r
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\n" ); document.write( "\n" ); document.write( "Jim
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