document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=536948>Question 536948</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A motorboat traveling with the current went 72 miles in 4 hours.  Going against the current, it tool 6 hours to travel the same distance.  Find the rate of the boat in calm water and the rate of the current.  I came up with 15 mph for the rate of the boat and 3 mph for the rate of the current.  Can someone tell me if these are correct? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #352663 by </B><A HREF=/tutors/aboutme.mpl?userid=lmeeks54><B>lmeeks54(111)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lmeeks54><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=lmeeks54><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=352663\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You've got it.  72 miles in 4 hours is 18 mph going downstream.  The same 72 miles upstream takes 6 hours, that's 12 mph.  If the boat's speed is constant and the current is constant, then you can assume the boat goes a constant 15 mph in calm water and is thus sped up 3 mph downstream and slowed down 3 mph upstream.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "Great job,<BR>\n" );
document.write( "Lee </SPAN>\n" );
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