document.write( "Question 536711: If a bus traveled 10km/h faster, it would take 2 hours less time to make a 315km trip. What is its speed?\r
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Algebra.Com's Answer #352619 by ankor@dixie-net.com(22740)\"\" \"About 
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If a bus traveled 10km/h faster, it would take 2 hours less time to make a 315km trip.
\n" ); document.write( "What is its speed?
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\n" ); document.write( "Let s = the speed of the bus
\n" ); document.write( "then
\n" ); document.write( "(s+10) = the faster speed
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\n" ); document.write( "Write time equation, time = dist/speed
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\n" ); document.write( "Actual time - faster time = 2 hrs
\n" ); document.write( "\"315%2Fs\" - \"315%2F%28%28s%2B10%29%29\" = 2
\n" ); document.write( "multiply by s(s+10)
\n" ); document.write( "s(s+10)*\"315%2Fs\" - s(s+5)*\"315%2F%28%28s%2B10%29%29\" = 2s(s+10)
\n" ); document.write( "Cancel the denominators and you have
\n" ); document.write( "315(s+10) - 315s = 2s^2 + 20s
\n" ); document.write( "315s + 3150 - 315s = 2s^2 + 20s
\n" ); document.write( "0 = 2s^2 + 20s - 3150
\n" ); document.write( "Simplify, divide by 2
\n" ); document.write( "s^2 + 10s - 1575 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(s+45)(s-35) = 0
\n" ); document.write( "The positive solution
\n" ); document.write( "s = 35 mph is the actual bus speed
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\n" ); document.write( "Check this by finding the times at each speed
\n" ); document.write( "315/35 = 9 hrs
\n" ); document.write( "315/45 = 7 hrs
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