document.write( "Question 536711: If a bus traveled 10km/h faster, it would take 2 hours less time to make a 315km trip. What is its speed?\r
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document.write( "Thanks for any help:) \n" );
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Algebra.Com's Answer #352619 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! If a bus traveled 10km/h faster, it would take 2 hours less time to make a 315km trip. \n" ); document.write( "What is its speed? \n" ); document.write( ": \n" ); document.write( "Let s = the speed of the bus \n" ); document.write( "then \n" ); document.write( "(s+10) = the faster speed \n" ); document.write( ": \n" ); document.write( "Write time equation, time = dist/speed \n" ); document.write( ": \n" ); document.write( "Actual time - faster time = 2 hrs \n" ); document.write( " \n" ); document.write( "multiply by s(s+10) \n" ); document.write( "s(s+10)* \n" ); document.write( "Cancel the denominators and you have \n" ); document.write( "315(s+10) - 315s = 2s^2 + 20s \n" ); document.write( "315s + 3150 - 315s = 2s^2 + 20s \n" ); document.write( "0 = 2s^2 + 20s - 3150 \n" ); document.write( "Simplify, divide by 2 \n" ); document.write( "s^2 + 10s - 1575 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(s+45)(s-35) = 0 \n" ); document.write( "The positive solution \n" ); document.write( "s = 35 mph is the actual bus speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this by finding the times at each speed \n" ); document.write( "315/35 = 9 hrs \n" ); document.write( "315/45 = 7 hrs \n" ); document.write( " \n" ); document.write( " |