document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=536789>Question 536789</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hey so i'm working on complex numbers in my algebra 2 class and I have not done my homework over all of the thanksgiving break.. hahha. So I need help on refreshing how to do it.  So for example would (5-8i)+(7+6i) be 12-2i or -13-26i? Or would (3+3i)-(-8+i) be -5+4i or -27+27i?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #352570 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=352570\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (5-8i)+(7+6i) is 12-2i, so your first answer is correct.\r<BR>\n" );
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document.write( "(3+3i)-(-8+i) is 11+2i, keep in mind that the negative distributes.\r<BR>\n" );
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document.write( "Jim </SPAN>\n" );
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