document.write( "Question 52821This question is from textbook
\n" ); document.write( ": It takes Terry 2 hours longer to do a certain job than it takes Tom. They worked together for 3 hours. Then Tom left and Terry finished the job in one hour. How long would it take each of them to do the job alone? \n" ); document.write( "
Algebra.Com's Answer #35257 by ankor@dixie-net.com(22740)\"\" \"About 
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It takes Terry 2 hours longer to do a certain job than it takes Tom. They worked together for 3 hours. Then Tom left and Terry finished the job in one hour. How long would it take each of them to do the job alone?
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\n" ); document.write( "Let the completed job = 1
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\n" ); document.write( "Let t = time required for Tom to complete it.
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\n" ); document.write( "Then [t+2] = Terry's time to do it.
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\n" ); document.write( "Working together, Tom worked 3 hrs and Terry worked 4 hrs.
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\n" ); document.write( " Tom + Terry = 1
\n" ); document.write( " 3/t + 4/(t+2) = 1
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\n" ); document.write( "Mult eq by t(t+2) and you have:
\n" ); document.write( " 3(t+2) + 4t = 1[t(t+2)]
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\n" ); document.write( " 3t + 6 + 4t = t^2 + 2t
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\n" ); document.write( " 0 = t^2 + 2t - 3t - 4t - 6
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\n" ); document.write( " 0 = t^2 - 5t - 6
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\n" ); document.write( " 0 = [t-6][t+1]
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\n" ); document.write( " t = +6
\n" ); document.write( " t = -1
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\n" ); document.write( "The positive solution is 6 hrs for Tom to do the job by himself
\n" ); document.write( "Then Terry would take 8 hrs to do it.
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\n" ); document.write( "Check by substitution: 3/6 + 4/8 = 1\r
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