document.write( "Question 536726: Two hoses are used to fill a water trough. The first hose can fill it in 20 minutes while the second hose needs only 16 minutes. If the second hose is used for the first 4 minutes and then the first is also used, how long will the first hose be used? \n" ); document.write( "
Algebra.Com's Answer #352556 by josmiceli(19441)\"\" \"About 
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What are their rates of filling the trough?
\n" ); document.write( "Hose 1: ( 1 trough ) / ( 20 min )
\n" ); document.write( "Hose 2: ( 1 trough ) / ( 16 min )
\n" ); document.write( "How much of the trough does hose 2 get
\n" ); document.write( "filled in the 1st 4 minutes?
\n" ); document.write( "\"+%281%2F16%29%2A4+=+1%2F4+\"
\n" ); document.write( "That means there is \"+3%2F4+\" of the trough
\n" ); document.write( "left to be filled using both hoses
\n" ); document.write( "Let \"t\" = time to fill 3/4 of trough with both hoses
\n" ); document.write( "---------
\n" ); document.write( "Add their rates of filling to get the rate
\n" ); document.write( "with both filling
\n" ); document.write( "\"+1%2F20+%2B+1%2F16+=+%283%2F4%29%2Ft+\"
\n" ); document.write( "\"+1%2F20+%2B+1%2F16+=+3%2F%284t%29++\"
\n" ); document.write( "Multiply both sides by \"4\"
\n" ); document.write( "\"+1%2F5+%2B+1%2F4+=+3%2Ft+\"
\n" ); document.write( "Multiply both sides by \"20t\"
\n" ); document.write( "\"+4t+%2B+5t+=+60+\"
\n" ); document.write( "\"+9t+=+60+\"
\n" ); document.write( "\"+t+=+6.667+\" min
\n" ); document.write( "\"+.667%2A60+=+40+\" sec
\n" ); document.write( "The 1st hose will be used for 6 min and 40 sec
\n" ); document.write( "check answer:
\n" ); document.write( "\"+1%2F20+%2B+1%2F16+=+%283%2F4%29%2Ft+\"
\n" ); document.write( "\"+.05+%2B+.0625+=+.75%2F6.667+\"
\n" ); document.write( "\"+.1125+=+.75%2F6.667+\"
\n" ); document.write( "\"+.7500375+=+.75+\" ( error is from rounding )
\n" ); document.write( "OK
\n" ); document.write( "
\n" );