document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=536693>Question 536693</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the dimensions of a rectangle whose width is 6 miles less than its length, and whose area is 91 square miles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #352537 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=352537\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area =	91	sq. 	miles												<BR>\n" );
document.write( "Length  	=		x	miles											<BR>\n" );
document.write( "Width 	= x	-6<BR>\n" );
document.write( "Area =	x	*	(x	-6)<BR>\n" );
document.write( "91	=	x^2	-6x			<BR>\n" );
document.write( "x^2 	-6	x	-91	=	0	\r<BR>\n" );
document.write( "\n" );
document.write( "x^2-13x+7x-91=0<BR>\n" );
document.write( "x(x-13)+7(x-13)=0<BR>\n" );
document.write( "(x-13)(x+7)=0<BR>\n" );
document.write( "x= 13 OR -7\r<BR>\n" );
document.write( "\n" );
document.write( "Ignore negative value<BR>\n" );
document.write( "Length =13 & width = 7miles						<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );