document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=536687>Question 536687</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the slope of a line perpendicular to the line that passes through(3,9) and (7,15) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #352534 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=352534\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x1		y1	x2	y2				<BR>\n" );
document.write( "3	*	9	7	15				<BR>\n" );
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document.write( "slope m =		(y2-y1)/(x2-x1)						<BR>\n" );
document.write( "(	15	-	9	)/(	7	-	3	) <BR>\n" );
document.write( "(	6	/	4	)  				<BR>\n" );
document.write( "m=		3/ 2\r<BR>\n" );
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document.write( "The slope of perpendicular line = -2/3 because m1*m2 = -1\r<BR>\n" );
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