document.write( "Question 536640: im not sure how to solve logarithmic and/or exponential equations! here is on of my questions... maybe some steps on how to find the answer would really help me!\r
\n" ); document.write( "\n" ); document.write( " $\"+log7%28x%2B1%29=log7%282xsquared-x-3%29+\"$ \n" ); document.write( "

Algebra.Com's Answer #352520 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Some general rules are
\n" ); document.write( " $\"+log%28a%29+%2B+log%28b%29+=+log%28a%2Ab%29+\"$
\n" ); document.write( " $\"+log%28a%29+-+log%28b%29+=+log%28a%2Fb%29+\"$
\n" ); document.write( " $\"+log%28a%5Eb%29+=+b%2Alog%28a%29+\"$
\n" ); document.write( "You can use the rules in both directions
\n" ); document.write( " $\"+log%287%2Cx%2B1%29=log%287%2C2x%5E2+-+x+-+3%29+\"$
\n" ); document.write( "The rule to apply here is:
\n" ); document.write( "If this is true: $\"+log%28a%2Cb%29+=+log%28a%2Cc%29+\"$ ,
\n" ); document.write( "then $\"+b+=+c+\"$ , so
\n" ); document.write( " $\"+x+%2B+1+=+2x%5E2+-+x+-+3+\"$
\n" ); document.write( " $\"+x+%2B+1+=+%282x+-+3%29%2A%28x+%2B+1%29+\"$ (I used trial and error)
\n" ); document.write( "Divide both sides by $\"+x+%2B+1+\"$
\n" ); document.write( " $\"+1+=+2x+-+3+\"$
\n" ); document.write( " $\"+2x+=+4+\"$
\n" ); document.write( " $\"+x+=+2+\"$
\n" ); document.write( "check answer:
\n" ); document.write( " $\"+log%287%2C2%2B1%29=log%287%2C2%2A2%5E2+-+2+-+3%29+\"$
\n" ); document.write( " $\"+log%287%2C3%29+=+log%287%2C+8+-+2+-+3%29+\"$
\n" ); document.write( " $\"+log%287%2C3%29+=+log%287%2C+3%29+\"$
\n" ); document.write( "OK \n" ); document.write( "

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