document.write( "Question 536670: x^2-14x+48<0\r
\n" ); document.write( "\n" ); document.write( "The answer choices are: A (4,12), B (6,8), C (-infinity,6) U (8, infinity), D (-infinity,6] U [8, infinity)
\n" ); document.write( "

Algebra.Com's Answer #352519 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
IF YOU CAN FACTOR (using the quadratic formula to help is allowed)
\n" ); document.write( "\"x%5E2-14x%2B48=%28x-8%29%28x-6%29\" so it will be positive for x<6 and for x>8, zero at x=6 and x=8 , and negative in between.
\n" ); document.write( "IF YOU WILL NOT FACTOR
\n" ); document.write( "The coefficient of the \"x%5E2\" term is positive (+1), so the parabola opens up (smiling shape). A parabola with that shape might be negative somewhere in the middle, but will definitely have positive y values at both ends. That eliminates answers C and D.
\n" ); document.write( "For x=10 \"x%5E2-14x%2B48=10%5E2-14%2A10%2B48=100-140%2B48=8\"
\n" ); document.write( "and that eliminates answer A.
\n" ); document.write( "
\n" ); document.write( "
\n" );