document.write( "Question 536659: A man can row at the rate of 5 mph in still water. He can row 10 miles upstream (against the current) in the same time that he can row 30 miles downstream (with the current). What is the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #352513 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! r*t=d \n" ); document.write( "t=d/r \n" ); document.write( "the two times are the same \n" ); document.write( "rate of current is r\r \n" ); document.write( "\n" ); document.write( "10/(5-r)=30/(5+r) \n" ); document.write( "r=5/2 \n" ); document.write( "check \n" ); document.write( "10/2.5=4 \n" ); document.write( "30/7.5=4 \n" ); document.write( "ok \n" ); document.write( " |