document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=536663>Question 536663</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use an inequality to solve the problem.  Be sure to show the inequality and all of your work.\r<BR>\n" );
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document.write( "One side of a rectangle is 14 inches and the other is x inches.  What values of x will make the perimeter at most 80 inches? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #352511 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=352511\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = 2L + 2W.<P><BR>\n" );
document.write( "In this case call L=14 and W=x.<P><BR>\n" );
document.write( "x may turn out to be more than 14 and L is usually the longer dimension.  But it really isn't important which is called L and which is W.<P><BR>\n" );
document.write( "At most 80 inches means P <=80. <P><BR>\n" );
document.write( "2(14) + 2x <= 80.<P><BR>\n" );
document.write( "28 + 2x <= 80<P><BR>\n" );
document.write( "Subtract 28 from both sides.<P><BR>\n" );
document.write( "2x <= 52<P><BR>\n" );
document.write( "Divide both sides by 2.<P><BR>\n" );
document.write( "x <= 26<P><BR>\n" );
document.write( "It turns out x is really the length, the longer measure, but it wasn't important to the calculation.<BR>\n" );
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