document.write( "Question 536646: Ann lived in Bristol and Amy lived in Fairvale. At 2:00 P.M. they left their respective towns and walked in opposite directions, with Amy walking twice as fast an Ann. By 4:00 P.M., they were 66km apart. if,instead, they had walked from the towns toward each other, they would have been 12km apart at 3:00 P.M. How far apart are the towns? \n" ); document.write( "
Algebra.Com's Answer #352495 by mananth(16946)\"\" \"About 
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Ann lived in Bristol and Amy lived in Fairvale. At 2:00 P.M. they left their respective towns and walked in opposite directions, with Amy walking twice as fast an Ann. By 4:00 P.M., they were 66km apart. if,instead, they had walked from the towns toward each other, they would have been 12km apart at 3:00 P.M. How far apart are the towns? \r
\n" ); document.write( "\n" ); document.write( "let the distance between towns be x miles\r
\n" ); document.write( "\n" ); document.write( "They move away from each other.
\n" ); document.write( "time = 2 hours
\n" ); document.write( "Distance = 66 km
\n" ); document.write( "Ann speed = y
\n" ); document.write( "Amy speed = 2y\r
\n" ); document.write( "\n" ); document.write( "Add up the speeds
\n" ); document.write( "=3y
\n" ); document.write( "66/3y=2
\n" ); document.write( "3y=66/2
\n" ); document.write( "3y=33
\n" ); document.write( "y=11 Ann speed
\n" ); document.write( "Amy speed = 22 kph\r
\n" ); document.write( "\n" ); document.write( "Their combined speed = 33 kph
\n" ); document.write( "They are 12 km away after 1 hour
\n" ); document.write( "so the distance between the towns = 33 +12 = 45 km\r
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