document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=536598>Question 536598</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The instructions say solve each equation by factoring, by taking square roots, or by graphing. When necessary,round your answer to the nearest hundredth.\r<BR>\n" );
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document.write( "The first problem is x^2-18x-40=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #352459 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=352459\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Check if it can be factored with reverse FOIL.<P><BR>\n" );
document.write( "Can you find factors of -40 that when added = -18?<P><BR>\n" );
document.write( "Factors of -40 are -40 and 1, -20 and 2, -10 and 4, -5 and 8 and the same factor pairs with the signs switched (40 and -1, for example).  Look at -20 and 2.  -20+2 = -18.  Those factors work.<P><BR>\n" );
document.write( "(x-20)(x+2)=0<P><BR>\n" );
document.write( "By the 0 product rule, set each =0 and solve for x.<P><BR>\n" );
document.write( "x-20=0  (Add 20 to both sides.)  x=20<P><BR>\n" );
document.write( "x+2=0  (Subtract 2 from both sides.) x=-2.<BR>\n" );
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