document.write( "Question 535852: if 3x+6=51,then x= \n" ); document.write( "
Algebra.Com's Answer #352425 by jim_thompson5910(35256)\"\" \"About 
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\"3x%2B6=51\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"3x=51-6\" Subtract \"6\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"3x=45\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2845%29%2F%283%29\" Divide both sides by \"3\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=15\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=15\"
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