document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=52830>Question 52830</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having trouble solving: 2k+ar=r-3y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #35240 by </B><A HREF=/tutors/aboutme.mpl?userid=rchill><B>rchill(405)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rchill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=35240\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It depends on what you're solving for; is it k, a, r, or y?  Solving for y, by subtracting r from both sides, we get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2k%2Bar-r=-3y ALIGN=MIDDLE  ALT=\"2k%2Bar-r=-3y\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Now divide both sides by -3 to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282k%2Bar-r%29%2F-3=y ALIGN=MIDDLE  ALT=\"%282k%2Bar-r%29%2F-3=y\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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