document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=52708>Question 52708</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Question 3:<BR>\n" );
document.write( "Solve for x:<BR>\n" );
document.write( "4x + 4/2 = 3(x + 1) &#8211; 2<BR>\n" );
document.write( "x =  \r<BR>\n" );
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document.write( "Question 4:<BR>\n" );
document.write( "Solve for x. Enter this answer as a fraction:<BR>\n" );
document.write( "6x &#8211; 3 = 2x &#8211; (4 &#8211; 3)/3<BR>\n" );
document.write( "x =  \r<BR>\n" );
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document.write( "Question 5:<BR>\n" );
document.write( "Solve for x:<BR>\n" );
document.write( "x/2 + x/3 = (3x + 2)/4<BR>\n" );
document.write( "x =  \r<BR>\n" );
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document.write( "Question 6:<BR>\n" );
document.write( "Solve for x:<BR>\n" );
document.write( "-4x &#8211; 2 = -6 &#8211; 2x<BR>\n" );
document.write( "x =  \r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #35238 by </B><A HREF=/tutors/aboutme.mpl?userid=rchill><B>rchill(405)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rchill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=35238\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'll solve one of them for you and you can do the other three as the process stays the same for all four.  To solve for x, you need to isolate x on either side of the '=' sign.  So, for question 3, let's eliminate that nasty denominator of 2 on the left side of the equation by multiplying both sides by 2.  Doing that gives us <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8x%2B4=6%28x%2B1%29-4 ALIGN=MIDDLE  ALT=\"8x%2B4=6%28x%2B1%29-4\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Expanding the right side yields <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8x%2B4=6x%2B6-4 ALIGN=MIDDLE  ALT=\"8x%2B4=6x%2B6-4\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8x%2B4=6x%2B2 ALIGN=MIDDLE  ALT=\"8x%2B4=6x%2B2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Subtracting 6x on both sides yields <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%2B4=2 ALIGN=MIDDLE  ALT=\"2x%2B4=2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Now subtract 4 from both sides and get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x=-2 ALIGN=MIDDLE  ALT=\"2x=-2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Dividing both sides by 2 yields <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=-1 ALIGN=MIDDLE  ALT=\"x=-1\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  To check this answer, substitute -1 in for x in the original equation, thusly:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2A%28-1%29%2B4%2F2=s%28-1%2B1%29-2 ALIGN=MIDDLE  ALT=\"4%2A%28-1%29%2B4%2F2=s%28-1%2B1%29-2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Expanding the equation gives us <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-4%2B2=0-2 ALIGN=MIDDLE  ALT=\"-4%2B2=0-2\"   DISABLED_style= \"max-width:90%; height:auto;\" > which simplifies to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-2=-2 ALIGN=MIDDLE  ALT=\"-2=-2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Because this is a true statement, our answer of x=-1 is correct.  You can do the other three problems by repeating the process. </SPAN>\n" );
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