document.write( "Question 536422: At the begining of a walk, Steve and Eve are 6.6 mies apart. If they leave at the same time and wak in the same direction, Steve overtakes Eve in 11 hours. If they walk towards each other, they meet in 1 hour. What are their speeds? \n" ); document.write( "
Algebra.Com's Answer #352363 by mananth(16949)\"\" \"About 
You can put this solution on YOUR website!
steve speed= x
\n" ); document.write( "eve speed = \r
\n" ); document.write( "\n" ); document.write( "when they are walking in same direction the effective speed = x-y\r
\n" ); document.write( "\n" ); document.write( "d=6.6
\n" ); document.write( "t=11 hours
\n" ); document.write( "t=d/r\r
\n" ); document.write( "\n" ); document.write( "11= 6.6/(x-y)
\n" ); document.write( "11x-11y=6.6
\n" ); document.write( "x-y=0.66-------------------1\r
\n" ); document.write( "\n" ); document.write( "when they are walking towards each other speed = x+y\r
\n" ); document.write( "\n" ); document.write( "1=6.6/(x+y)
\n" ); document.write( "x+y=6.6---------------------2\r
\n" ); document.write( "\n" ); document.write( "Add equation (1) & (2)
\n" ); document.write( "2x=7.20
\n" ); document.write( "x=3.6 mph ----- steve's speed
\n" ); document.write( "plug x in (1)
\n" ); document.write( "3.6-y=0.66
\n" ); document.write( "3.6-0.66=y
\n" ); document.write( "2.94 =y -----------eve's speed
\n" ); document.write( " \n" ); document.write( "
\n" );