document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=536302>Question 536302</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Father age is 4 times as much as the sum of the ages of his three children but 6 years after his age will be only double the sum of his son age . Find  his age </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #352338 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=352338\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let sum of ages of children be x\r<BR>\n" );
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document.write( "Father's age = 4x<BR>\n" );
document.write( "After 6 years father's age = 4x+6<BR>\n" );
document.write( "sum of children's age = x+3*6=x+18 ( each child's age increases by 6 so three children's age will increase by 18)\r<BR>\n" );
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document.write( "4x+6=x+18<BR>\n" );
document.write( "3x=12<BR>\n" );
document.write( "x=12\r<BR>\n" );
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document.write( "Father's age = 12*4=48 years\r<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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