document.write( "Question 52809: I need help with the following questions.\r
\n" ); document.write( "\n" ); document.write( "A woman jogging at 6 mi/h passes a man biking in the opposite direction at 12 mi/h. If they maintain their speeds, how far from each other will they be 10 minutes after passing?\r
\n" ); document.write( "\n" ); document.write( "DO I need to multiple each by 10 and then add them together. For example they will be 180 miles apart?
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Algebra.Com's Answer #35233 by funmath(2933)\"\" \"About 
You can put this solution on YOUR website!
Almost!!! I almost said you were right. But as you probably thought, \"180 miles is a lot of mile to cover by jogging and biking in ten minutes!\"\r
\n" ); document.write( "\n" ); document.write( "Here's what you're missing:\r
\n" ); document.write( "\n" ); document.write( "You have to convert t=10min into hours
\n" ); document.write( "\"t=%2810min%2F1%29%2A%281hr%2F60min%29\"
\n" ); document.write( "t=1/6 hr\r
\n" ); document.write( "\n" ); document.write( "d=rt
\n" ); document.write( "Woman's distance:6(1/6)=1 miles
\n" ); document.write( "Man's distance:12(1/6)=2 miles
\n" ); document.write( "Total distance between them:
\n" ); document.write( "d=1+2
\n" ); document.write( "d=3 miles
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