document.write( "Question 536317: Find the equation of the circle of radius 5 whose centre lies on x-axis and passes through the point (2,3). \n" ); document.write( "
Algebra.Com's Answer #352258 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
The distance from the x-axis to (2,3) is the radius, r = 5.
\n" ); document.write( "There are 2 points in the x-axis that are 5 units from the point (2,3).
\n" ); document.write( "The points are (x,0).
\n" ); document.write( "\"d%5E2+=+25+=+diffy%5E2+%2B+diffx%5E2+=+3%5E2+%2B+%282-x%29%5E2\"
\n" ); document.write( "\"x%5E2+-+4x+%2B+13+=+25\"
\n" ); document.write( "\"x%5E2+-+4x+-+12+=+0\"
\n" ); document.write( "(x - 6)*(x + 2) = 0
\n" ); document.write( "x = -2, x = 6
\n" ); document.write( "------------\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%5E2+%2B+y%5E2+=+5%5E2\" Circle 1
\n" ); document.write( "\"%28x-6%29%5E2+%2B+y%5E2+=+5%5E2\" Circle 2
\n" ); document.write( "
\n" ); document.write( "
\n" );