document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=536325>Question 536325</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find 4 consecutive odd integers such that the sum of the second and the fourth is 63 more than one fifth of the third.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #352256 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=352256\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Four consecutive odd integers can be defined as:<BR>\n" );
document.write( "x<BR>\n" );
document.write( "x+2<BR>\n" );
document.write( "x+4<BR>\n" );
document.write( "x+6<BR>\n" );
document.write( ".<BR>\n" );
document.write( "The sum of the second and fourth:  x+2 + x+6 = 2x+8.<BR>\n" );
document.write( "Is 63 more than 1/5*(x+4).<BR>\n" );
document.write( ".<BR>\n" );
document.write( "2x+8-63 = 1/5*(x+4)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "2x -55 = 1/5(x+4)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Multiply both sides by 5 to eliminate fraction<BR>\n" );
document.write( ".<BR>\n" );
document.write( "5(2x -55) = 5/5*(x+4)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "10x -275 = x + 4<BR>\n" );
document.write( ".<BR>\n" );
document.write( "9x = 279<BR>\n" );
document.write( ".<BR>\n" );
document.write( "x = 31<BR>\n" );
document.write( ".<BR>\n" );
document.write( "So the four consecutive odd integers are:  31, 33, 35, and 37. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );