document.write( "Question 536184: I dont know what to do!\r
\n" ); document.write( "\n" ); document.write( "At the Stop 'n Go tune-up and brake shop, the manager has found that an SUV will require a tune-up with a probability of 0.6, a brake job with a probability of 0.1 and both with a probability of 0.02. What is the probability that an SUV requires neither type of repair? \n" ); document.write( "
Algebra.Com's Answer #352222 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Let P(tu) = the probability of a tune-up and P(b) = the probability of a brake job.
\n" ); document.write( "P(tu) = 0.6 and P(b) = 0.1
\n" ); document.write( "P(tu and b) = 0.2
\n" ); document.write( "The probability of neither is just 1-P(tu and b) = 1-0.2 = 0.8
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\n" ); document.write( "This answer is incorrect!
\n" ); document.write( "First, the P(tu and b) is 0.02 not 0.2.
\n" ); document.write( "Second:The probability of tu or b is:
\n" ); document.write( "P(tu or b) = P(tu)+P(b)-P(tu and b) if the events are not mutually exclusive.
\n" ); document.write( "P(tu or b) = 0.6+0.1-0.02 = 0.7-0.02 = 0.68
\n" ); document.write( "The probability of neither Tu nor b is 1-P(tu or b) = 1-0.68 = 0.32
\n" ); document.write( "If they are mutually exclusive then:
\n" ); document.write( "P(tu or b) = P(tu)+P(b) = 0.6+0.1 = 0.7 and neither would be 1-0.7 = 0.3 which is not on your list of answers.
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