document.write( "Question 536199: Write the equation of a line, in slope-intercept form, that is perpendicular to: -8x + 3y + 7 = -6\r
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Algebra.Com's Answer #352189 by oberobic(2304) $\"\"$ $\"About$

You can put this solution on YOUR website!
-8x + 3y +7 = -6
\n" ); document.write( "-8x + 3y = -13
\n" ); document.write( "3y = 8x -13
\n" ); document.write( "y = 8/3*x -13/3
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\n" ); document.write( "When x=0, y=-13/3
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\n" ); document.write( "When y = 0,
\n" ); document.write( "-8/3*x = -13/3
\n" ); document.write( "cross multiply
\n" ); document.write( "-8x*3 = 3*-13
\n" ); document.write( "-24x = -39
\n" ); document.write( "x = 39/24 = 13/8
\n" ); document.write( "so
\n" ); document.write( "x = 13/8, y =0
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\n" ); document.write( "The equation of the line perpendicular to y = 8/3*x -13/3 will have the slope = to the inverse reciprocal of the 8/3, which = -3/8.
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\n" ); document.write( "y = -3/8x
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\n" ); document.write( "This line does not have to go through any specific point, so you can leave it there.
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\n" ); document.write( " $\"+graph%28500%2C500%2C-5%2C5%2C-5%2C5%2C8%2F3%2Ax+-13%2F3%2C-3%2F8%2Ax%29+\"$ \n" ); document.write( "

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