document.write( "Question 536131: im a 3-digit number divisible by 3.my tens digit is 3 times greatas my hundreds digit, and the sum of digits is 15. if you reverse my digits,im divisible by 6,as well as by 3.
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document.write( "what number am i? \n" );
document.write( "
Algebra.Com's Answer #352180 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! im a 3-digit number divisible by 3.my tens digit is 3 times greatas my hundreds digit, and the sum of digits is 15. if you reverse my digits,im divisible by 6,as well as by 3. \n" ); document.write( "what number am i? \n" ); document.write( "** \n" ); document.write( "let u=units digit \n" ); document.write( "let t=tens digit \n" ); document.write( "let h=hundreds digit \n" ); document.write( ".. \n" ); document.write( "u+t+h=15 \n" ); document.write( "t=3h \n" ); document.write( "possible ten and hundred digits: \n" ); document.write( "t=3, h=1 \n" ); document.write( "u+3+1=15 \n" ); document.write( "u=15-4=11 \n" ); document.write( "u≠11 \n" ); document.write( ".. \n" ); document.write( "t=6, h=2 \n" ); document.write( "u+6+2=15 \n" ); document.write( "u=15-8=7 \n" ); document.write( "u=7 \n" ); document.write( "number:762 \n" ); document.write( "Check: \n" ); document.write( "762/3=254 \n" ); document.write( "762/6=127 \n" ); document.write( "ans: \n" ); document.write( "The number is 762 \n" ); document.write( " |