document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=536151>Question 536151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the solution of logarithm logx+log(x+1)=2log(1-x) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #352168 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=352168\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> what is the solution of logarithm logx+log(x+1)=2log(1-x)<BR>\n" );
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document.write( "logx+log(x+1)=2log(1-x)<BR>\n" );
document.write( "logx+log(x+1)-2log(1-x)=0<BR>\n" );
document.write( "place under single log<BR>\n" );
document.write( "log[(x(x+1))/((1-x)^2)]=0<BR>\n" );
document.write( "convert to exponential form: base(10) raised to log of number(0)=number(x(x+1))/((1-x)^2)<BR>\n" );
document.write( "10^0=1=(x(x+1))/((1-x)^2)<BR>\n" );
document.write( "x(x+1)=(1-x)^2<BR>\n" );
document.write( "x^2+x=1-2x+x^2<BR>\n" );
document.write( "3x=1<BR>\n" );
document.write( "x=1/3 </SPAN>\n" );
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