document.write( "Question 536147: 1) Given the points (-2,-3) & (4,-4) write an equation for a line which passes through these two points\r
\n" ); document.write( "\n" ); document.write( "2) Given the points (t,7) & (-5,3) find the value of t such that the slope of the line containing these points is -8. \n" ); document.write( "
Algebra.Com's Answer #352165 by lwsshak3(11628)\"\" \"About 
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1) Given the points (-2,-3) & (4,-4) write an equation for a line which passes through these two points
\n" ); document.write( "2) Given the points (t,7) & (-5,3) find the value of t such that the slope of the line containing these points is -8
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\n" ); document.write( "Standard form of an equation for a straight line: y=mx+b, m=slope, b=y-intercept
\n" ); document.write( "..
\n" ); document.write( "1) slope=∆y/∆x=(y1-y2)/(x1-x2)=rise/run=(-4-(-3))/(4-(-2))=(-4+3)/(4+2)=-1/6
\n" ); document.write( "Equation: y=(-1/6)x+b=-x/6+b
\n" ); document.write( "solving for b using coordinates of one of the given points(4,-4)
\n" ); document.write( "-4=-4/6+b
\n" ); document.write( "b=-4+4/6=-24/6+4/6=-20/6=-10/3
\n" ); document.write( "Equation of line: y=-x/6-10/32
\n" ); document.write( "..
\n" ); document.write( "2)slope=∆y/∆x=(3-7)/(-5-t)=-4/(-5-t)=-8
\n" ); document.write( "40+8t=-4
\n" ); document.write( "8t=-44
\n" ); document.write( "t=-44/8=-5.5 \n" ); document.write( "
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