document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=536128>Question 536128</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you write 5^x-7=9^-9x as a 10 logrithm finding the value of x.  Thanks for your help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #352161 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=352161\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how do you write 5^x-7=9^-9x as a 10 logrithm finding the value of x. <BR>\n" );
document.write( "..<BR>\n" );
document.write( "5^(x-7)=9^-9x<BR>\n" );
document.write( "take log of both sides using exponent rule<BR>\n" );
document.write( "(x-7) log5=-9xlog9<BR>\n" );
document.write( "(x-7)/9x=-log9/log5<BR>\n" );
document.write( "using calculator<BR>\n" );
document.write( "(x-7)/9x=-1.3652<BR>\n" );
document.write( "x-7=9x*-1.362=-12.2869x<BR>\n" );
document.write( "x+12.2869x=7<BR>\n" );
document.write( "13.2869x=7<BR>\n" );
document.write( "x=7/13.2869&#8776;.5268 </SPAN>\n" );
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