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You can put this solution on YOUR website!
Remember that log and exponents are inverse such that:
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document.write( "If b^y=x then log_b(x) = y.
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document.write( "5^(x-7)=9^(-9x) can be rewritten as: log_5(9^(-9x))=x-7
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document.write( "Remember log (x^y) = y*log(x).
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document.write( "Rewrite as: (-9x)*log_5(9)=x-7
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document.write( "Convert log_x to log_y with log_y(z) = log_x(z)/log_x(y)
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document.write( "We can convert from base-5 to base-10 in this case.
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document.write( "That gives: (-9x)*(log_10(9)/log_10(5)) = x-7.
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document.write( "Now evaluate the logs and complete the algebra.
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document.write( "-9x*(1.36521239)=x-7 ---> -12.2869115x=x-7 (subtract x from both sides)
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document.write( "-13.2869115x=-7 (divide both sides by -13.2869115) x=0.526834246\r
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