document.write( "Question 536046: Solve:\r
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document.write( "log(36,10x-11)+log(36,X)=1/2\r
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document.write( "i get to this point here: log(36,10x^2-11x)=1/2
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document.write( "but then im lost after\r
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document.write( "thanks\r
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document.write( "Angela \n" );
document.write( "
Algebra.Com's Answer #352107 by nerdybill(7384) You can put this solution on YOUR website! Solve: \n" ); document.write( "log(36,10x-11)+log(36,X)=1/2 \n" ); document.write( ". \n" ); document.write( "i get to this point here: \n" ); document.write( "log(36,10x^2-11x)=1/2 (so far, so good) \n" ); document.write( ". \n" ); document.write( "36^log(36,10x^2-11x) = 36^(1/2) \n" ); document.write( "10x^2-11x = 36^(1/2) \n" ); document.write( "10x^2-11x = 6 \n" ); document.write( ". \n" ); document.write( "10x^2-11x = 6 \n" ); document.write( "10x^2-11x - 6= 0 \n" ); document.write( "10x^2 -15x+4x - 6= 0 \n" ); document.write( "(10x^2-15x) + (4x-6) = 0 \n" ); document.write( "5x(2x-3) + 2(2x-3) = 0 \n" ); document.write( "(2x-3)(5x+2) = 0 \n" ); document.write( "x = {3/2, -2/5} \n" ); document.write( "throw out the negative solution (extraneous) leaving: \n" ); document.write( "x = 3/2\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |