document.write( "Question 535714: vertex form y=-x^2+6x+4 \r
\n" ); document.write( "\n" ); document.write( "i need in vertex form i cant find out how to do it?
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Algebra.Com's Answer #352103 by KMST(5328)\"\" \"About 
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\"y=-x%5E2%2B6x%2B4\"
\n" ); document.write( "Noticing that 6x is double the product of x and 3, I see the first two terms as part of a square. I add and subtract 9 (the square of 3), and group to get
\n" ); document.write( "\"y=%28-x%5E2%2B6x-9%29%2B9%2B4\"
\n" ); document.write( "I know that \"-%28x-3%29%5E2=-%28x%5E2-6x%2B9%29=-x%5E2%2B6x-9\" and just \"completed the square.\"
\n" ); document.write( "That gets me to the equation of the parabola in vertex form:
\n" ); document.write( "\"y=-%28x-3%29%5E2%2B13\"
\n" ); document.write( "That form of the equation equation tells you the axis of symmetry of the parabola is \"x=3\"
\n" ); document.write( "and the vertex is at (3,13).
\n" ); document.write( "To get the vertex form, you could \"complete the square\" as I did, or you could try to memorize an unwieldy formula handed down by someone who just did the same work with the generic parabola equation \"y=ax%5E2%2Bbx%2Bc\"
\n" ); document.write( "to come up with the formula for the vertex form:
\n" ); document.write( "\"y=a%28x%2Bb%2F2a%29%5E2%2B%284ac-b%5E2%29%2F4a\"
\n" ); document.write( "In your case, your a, b, and c values were:
\n" ); document.write( "\"a=-1\", \"b=6\", and \"c=4\"
\n" ); document.write( "If you substitute a, b and c in the monster formula you get your vertex form.
\n" ); document.write( "Admittedly, there is an in-between way:
\n" ); document.write( "You could just remember the formula for the axis: \"x=-b%2F2a\",
\n" ); document.write( "which gives you the x-coordinate for the vertex, calculate the value to know what to subtract from x in the vertex form, and then calculate the y-coordinate for the vertex, which is also the last term of the vertex form, by substituting the x-coordinate for the vertex in the equation for the parabola
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