document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=535733>Question 535733</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone help me solve this\r<BR>\n" );
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document.write( "An experienced man constructs a wall in 3 hours. The apprentice completes the job in 6 hours. How long does it take if they work together? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #352073 by </B><A HREF=/tutors/aboutme.mpl?userid=april4869><B>april4869(19)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=april4869><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=april4869><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=352073\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Part of the job done by the experienced man in one hour is 1/3. <BR>\n" );
document.write( "Part of the job done by the apprentice in one hour is 1/6.<BR>\n" );
document.write( "Let x=their time together.  So part of the job done in one hour together is 1/x<BR>\n" );
document.write( "Think: part done by man + part done by apprentice = part done together<BR>\n" );
document.write( "1/3+1/6=1/x<BR>\n" );
document.write( "Now multiply by 6x<BR>\n" );
document.write( "2x + x = 6<BR>\n" );
document.write( "3x = 6<BR>\n" );
document.write( "x = 2\r<BR>\n" );
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document.write( "So they can get the job done together in two hours. <BR>\n" );
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