document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=535984>Question 535984</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (x+3)/x > 0 \r<BR>\n" );
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document.write( "I have no idea what to do </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #352064 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=352064\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x+3)/x > 0 <BR>\n" );
document.write( "When x+3=0 then the function = 0. x+3=0 when x=-3.<BR>\n" );
document.write( "when the denominator=0 then the function is undefined. The denominator=0 when x=0.<BR>\n" );
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document.write( "when x<-3: make x=-5: (-5+3)/-5 = 2/5 the function > 0<BR>\n" );
document.write( "when x>-3 and x<0 make x=-1: (-1+3)/-1 = -2/1 = -2 the function < 0<BR>\n" );
document.write( "when x>0: make x=1: (1+3)/1 = 4 the function > 0<BR>\n" );
document.write( "ANSWER: X(-infinity, -3) U (0, infinity)<BR>\n" );
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document.write( "Ed<BR>\n" );
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