document.write( "Question 535888: If computer a can process 10 pictures in 180 sec, and working toghether with computer b, processes them in 100 sec, how long does it take for b to process the same amount of pictures \n" ); document.write( "
Algebra.Com's Answer #352035 by ankor@dixie-net.com(22740)\"\" \"About 
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If computer a can process 10 pictures in 180 sec, and working together with computer b, processes them in 100 sec,
\n" ); document.write( " how long does it take for b to process the same amount of pictures
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\n" ); document.write( "let b = time required by b alone
\n" ); document.write( "let the completed job = 1 (10 pics processed)
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\n" ); document.write( "A typical shared work equation
\n" ); document.write( "\"100%2F180\" + \"100%2Fb\" = 1
\n" ); document.write( "mult by 180b
\n" ); document.write( "180b*\"100%2F180\" + 180b*\"100%2Fb\" = 180b
\n" ); document.write( "Cancel the denominators and you have
\n" ); document.write( "100b + 180(100) = 180b
\n" ); document.write( "18000 = 180b - 100b
\n" ); document.write( "18000 = 80b
\n" ); document.write( "b = \"18000%2F80\"
\n" ); document.write( "b = 225 sec alone
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