document.write( "Question 535914: If Kyle drove the first 40 miles and I droved the last leg of the drive. Taking the same route home Kyle drove the first leg and I drove the last 50 miles. \r
\n" ); document.write( "\n" ); document.write( "Who drove the most and by how much?\r
\n" ); document.write( "\n" ); document.write( "I have tried putting this into a trigonometry distance formula as well as an algerbraic formula (40x=50x) then dividing them both by 50 which will become: x=40x/50, I configured it to x=.8x. I am lost on where to go from there if I am even on the correct track. Thank you for your time and help. \n" ); document.write( "

Algebra.Com's Answer #352027 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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If Kyle drove the first 40 miles and I droved the last leg of the drive.
\n" ); document.write( " Taking the same route home Kyle drove the first leg and I drove the last 50 miles.
\n" ); document.write( "Who drove the most and by how much?
\n" ); document.write( ":
\n" ); document.write( "Let h = dist of the last leg of the outbound trip (which he drove)
\n" ); document.write( "then
\n" ); document.write( "(h+40) = total one-way distance
\n" ); document.write( ":
\n" ); document.write( "\"Taking the same route home Kyle drove the first leg and I drove the last 50 miles.\"
\n" ); document.write( "Find the dist Kyle drove (k)
\n" ); document.write( "K = (h+40) - 50
\n" ); document.write( "k = h - 10
\n" ); document.write( "Therefore h drove 10 more miles than k (Kyle) \n" ); document.write( "

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