document.write( "Question 535794: I have an exam in just a little more than an hour. I am going over my review for the exam and there are 2 problems that I have the answers for, because they have given us that but I need to know how to go about solving the probelems. Anyone's help is greatly appreciated!!!\r
\n" ); document.write( "\n" ); document.write( "_x+4_ = _x+10___
\n" ); document.write( "x-3 x+2\r
\n" ); document.write( "\n" ); document.write( "Not sure if this makes any sense... I am not sure how to type this up.. It is fractions. x+4 is over x-3 and then it is = in the middle with x+10 above x+2.\r
\n" ); document.write( "\n" ); document.write( "The other one that I am struggling with is this\r
\n" ); document.write( "\n" ); document.write( "__5__ + _3__ = 1
\n" ); document.write( "3x x\r
\n" ); document.write( "\n" ); document.write( "This is the same it is a fraction but instead of it being a fraction at the end it is an equals sign with a 1. Thanks so much!
\n" ); document.write( "

Algebra.Com's Answer #352005 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve:
\n" ); document.write( "1) \"%28x%2B4%29%2F%28x-3%29+=+%28x%2B10%29%2F%28x%2B2%29\" Cross-multiply.
\n" ); document.write( "\"%28x%2B4%29%28x%2B2%29+=+%28x%2B10%29%28x-3%29\" Perform the indicated multiplication.
\n" ); document.write( "\"x%5E2%2B6x%2B8+=+x%5E2%2B7x-30\" Subtract \"x%5E2\" from both sides.
\n" ); document.write( "\"6x%2B8+=+7x-30\" Subtract 6x from both sides.
\n" ); document.write( "\"8+=+x-30\" Add 30 to both sides.
\n" ); document.write( "\"38+=+x\" or \"highlight%28x+=+38%29\"
\n" ); document.write( "---------------------------------------
\n" ); document.write( "2) \"5%2F%283x%29%2B3%2Fx+=+1\" Use the common denominator of 3x to add the two fractions.
\n" ); document.write( "\"5%2F%283x%29%2B3%2A3%2F3x+=+1\"
\n" ); document.write( "\"%285%2B9%29%2F3x+=+1\" Multiply boh sides by 3x.
\n" ); document.write( "\"14+=+3x\" Divide both sides by 3.
\n" ); document.write( "\"14%2F3+=+x\" or \"x+=+4\"\"2%2F3\"
\n" ); document.write( "
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