document.write( "Question 535785: y=-2x^2+6 How do I graph this? \n" ); document.write( "
Algebra.Com's Answer #352001 by lwsshak3(11628)\"\" \"About 
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y=-2x^2+6 How do I graph this?
\n" ); document.write( "This is an equation of the standard form for a parabola: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex.
\n" ); document.write( "For given equation:
\n" ); document.write( "vertex:(0,6)
\n" ); document.write( "negative lead coefficient means parabola opens downwards
\n" ); document.write( "y-intercept
\n" ); document.write( "set x=0
\n" ); document.write( "y=6
\n" ); document.write( "..
\n" ); document.write( "x-intercepts:
\n" ); document.write( "set y=0
\n" ); document.write( "2x^2=6
\n" ); document.write( "x^2=3
\n" ); document.write( "x=±√3
\n" ); document.write( "..
\n" ); document.write( "you now have the vertex(0,6), y-intercept(0,6) and two x-intercepts(±√3,0)
\n" ); document.write( "with which you can easily draw the graph of given function. \n" ); document.write( "
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