document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1186>Question 1186</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A golfer hits a ball that reaches a height of 24 metres after 2 seconds. If the ball stays in the air for a total of 6 seconds, what was its maximum height? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #352 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Let Vo be the initial vertical velocity of the ball.<BR>\n" );
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document.write( " Since h = vot - 1/2 gt^2, <BR>\n" );
document.write( " and we know h = 24 m when t = 2 sec, we have<BR>\n" );
document.write( " 24 = 2 Vo - 2*9.8 ,<BR>\n" );
document.write( " 2 Vo = 24 + 19.6 = 43.6,<BR>\n" );
document.write( " So Vo = 21.8 m/s<BR>\n" );
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document.write( " By the formula V^2 = Vo^2 - 2g h and so h is maximum when V =0,<BR>\n" );
document.write( " so h(max) = Vo^2 / 2g = (21.8)^2 / 19.6 = 24.25 meters\r<BR>\n" );
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document.write( " Answwer: Maximum height is 24.25 meters<BR>\n" );
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